#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main()
{
    int n, i, sum=0;
    char num[110];
   
    scanf("%d",&n);
    scanf("%s",num);
   
    for(i=0; i<n; i++){
        sum+=atoi(&num[i]);
    }
    printf("%d\n",sum);
    return 0;
}

이렇게 푸니까 자꾸 안풀리더라구요...

왜안되는걸까요..

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main()
{
    int n, i, sum=0;
    char num[110];
   
    scanf("%d",&n);
    scanf("%s",num);
   
    for(i=0; i<n; i++){
        switch(num[i]){
            case 48: sum+=0; break;
            case 49: sum+=1; break;
            case 50: sum+=2; break;
            case 51: sum+=3; break;
            case 52: sum+=4; break;
            case 53: sum+=5; break;
            case 54: sum+=6; break;
            case 55: sum+=7; break;
            case 56: sum+=8; break;
            case 57: sum+=9; break;
        }
    }
    printf("%d\n",sum);
    return 0;
}

이렇게 아스키코드값을 이용해서 더럽게 풀었는데 찜찜해서 질문드립니다 ㅠ