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문제

어떠한 다이아몬드의 가치는 그 다이아몬드의 중량인 캐럿과 선명도에 의해서 결정됩니다. 즉, 작지만 선명한 다이아몬드가 크고 선명하지 않은 다이아몬드보다는 가치가 높습니다. 다이아몬드의 선명도는 0.0-10.0의 스캐일로 표현할 수 있는데, 0.0의 선명도는 완벽하게 선명한 다이아몬드를 나타내고 10.0은 가장 결함이 많은 다이아몬드를 나타냅니다.

N개의 다이아몬드의 중량 wi와 선명도 ci의 정보가 주어졌을때, 이 중에서 다이아몬드의 중량이 높아지고, 선명도 값이 낮아지는 부분열 중 최장의 것의 길이를 구하세요. 예를들어 주어진 정보가 다음과 같다면

wi ci
1.5 9.0
2.0 2.0
2.5 6.0
3.0 5.0
4.0 2.0
10.0 5.5

다이아몬드 중량이 높아지고, 선명도 값이 낮아지는 부분열 중 길이가 최장인 것은 다음과 같습니다.

1.5 9.0
2.5 6.0
3.0 5.0
4.0 2.0

왜냐하면 표에 나와있는 부분열을 보면, 무게는 증가하고, 선명도의 값은 감소하기 때문입니다.

입력

테스트 케이스의 개수 T가 주어지고 (1≤T≤100) 각 테스트 케이스마다 다이아몬드의 정보의 개수 N (1≤N≤200)이 주어집니다. 그리고 N개의 줄에 걸쳐서 다이아몬드의 무게와 선명도 wi, ci가 주어집니다 (0≤wi,ci≤100).

출력

각 테스트 케이스마다 다이아몬드의 가치가 높아지는 부분열중 최장의 것의 길이를 구하세요.

예제 입력 1

3
2
1.0 1.0
1.5 0.0
3
1.0 1.0
1.0 1.0
1.0 1.0
6
1.5 9.0
2.0 2.0
2.5 6.0
3.0 5.0
4.0 2.0
10.0 5.5

예제 출력 1

2
1
4
[{"problem_id":"10571","problem_lang":"0","title":"\ub2e4\uc774\uc544\ubaac\ub4dc","description":"<p style=\"text-align:center\"><img alt=\"\" src=\"\/upload\/images2\/diamond.png\" style=\"height:72px; width:210px\" \/><\/p>\r\n\r\n<p>\uc5b4\ub5a0\ud55c \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uac00\uce58\ub294 \uadf8 \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uc911\ub7c9\uc778 \uce90\ub7ff\uacfc \uc120\uba85\ub3c4\uc5d0 \uc758\ud574\uc11c \uacb0\uc815\ub429\ub2c8\ub2e4. \uc989, \uc791\uc9c0\ub9cc \uc120\uba85\ud55c \ub2e4\uc774\uc544\ubaac\ub4dc\uac00 \ud06c\uace0 \uc120\uba85\ud558\uc9c0 \uc54a\uc740 \ub2e4\uc774\uc544\ubaac\ub4dc\ubcf4\ub2e4\ub294 \uac00\uce58\uac00 \ub192\uc2b5\ub2c8\ub2e4. \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uc120\uba85\ub3c4\ub294 0.0-10.0\uc758 \uc2a4\uce90\uc77c\ub85c \ud45c\ud604\ud560 \uc218 \uc788\ub294\ub370, 0.0\uc758 \uc120\uba85\ub3c4\ub294 \uc644\ubcbd\ud558\uac8c \uc120\uba85\ud55c \ub2e4\uc774\uc544\ubaac\ub4dc\ub97c \ub098\ud0c0\ub0b4\uace0 10.0\uc740 \uac00\uc7a5 \uacb0\ud568\uc774 \ub9ce\uc740 \ub2e4\uc774\uc544\ubaac\ub4dc\ub97c \ub098\ud0c0\ub0c5\ub2c8\ub2e4.<\/p>\r\n\r\n<p>N\uac1c\uc758 \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uc911\ub7c9 w<sub>i<\/sub>\uc640 \uc120\uba85\ub3c4 c<sub>i<\/sub>\uc758 \uc815\ubcf4\uac00 \uc8fc\uc5b4\uc84c\uc744\ub54c, \uc774 \uc911\uc5d0\uc11c \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uc911\ub7c9\uc774 \ub192\uc544\uc9c0\uace0, \uc120\uba85\ub3c4 \uac12\uc774 \ub0ae\uc544\uc9c0\ub294 \ubd80\ubd84\uc5f4 \uc911 \ucd5c\uc7a5\uc758 \uac83\uc758 \uae38\uc774\ub97c \uad6c\ud558\uc138\uc694. \uc608\ub97c\ub4e4\uc5b4 \uc8fc\uc5b4\uc9c4 \uc815\ubcf4\uac00 \ub2e4\uc74c\uacfc \uac19\ub2e4\uba74<\/p>\r\n\r\n<table class=\"table table-bordered\" style=\"width: 30%;\">\r\n\t<tbody>\r\n\t\t<tr>\r\n\t\t\t<td>w<sub>i<\/sub><\/td>\r\n\t\t\t<td>c<sub>i<\/sub><\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>1.5<\/td>\r\n\t\t\t<td>9.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>2.0<\/td>\r\n\t\t\t<td>2.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>2.5<\/td>\r\n\t\t\t<td>6.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>3.0<\/td>\r\n\t\t\t<td>5.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>4.0<\/td>\r\n\t\t\t<td>2.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>10.0<\/td>\r\n\t\t\t<td>5.5<\/td>\r\n\t\t<\/tr>\r\n\t<\/tbody>\r\n<\/table>\r\n\r\n<p>\ub2e4\uc774\uc544\ubaac\ub4dc \uc911\ub7c9\uc774 \ub192\uc544\uc9c0\uace0, \uc120\uba85\ub3c4 \uac12\uc774 \ub0ae\uc544\uc9c0\ub294 \ubd80\ubd84\uc5f4 \uc911 \uae38\uc774\uac00 \ucd5c\uc7a5\uc778 \uac83\uc740 \ub2e4\uc74c\uacfc \uac19\uc2b5\ub2c8\ub2e4.<\/p>\r\n\r\n<table class=\"table table-bordered\" style=\"width: 30%;\">\r\n\t<tbody>\r\n\t\t<tr>\r\n\t\t\t<td>1.5<\/td>\r\n\t\t\t<td>9.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>2.5<\/td>\r\n\t\t\t<td>6.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>3.0<\/td>\r\n\t\t\t<td>5.0<\/td>\r\n\t\t<\/tr>\r\n\t\t<tr>\r\n\t\t\t<td>4.0<\/td>\r\n\t\t\t<td>2.0<\/td>\r\n\t\t<\/tr>\r\n\t<\/tbody>\r\n<\/table>\r\n\r\n<p>\uc65c\ub0d0\ud558\uba74 \ud45c\uc5d0 \ub098\uc640\uc788\ub294 \ubd80\ubd84\uc5f4\uc744 \ubcf4\uba74, \ubb34\uac8c\ub294 \uc99d\uac00\ud558\uace0, \uc120\uba85\ub3c4\uc758 \uac12\uc740 \uac10\uc18c\ud558\uae30 \ub54c\ubb38\uc785\ub2c8\ub2e4.<\/p>\r\n","input":"<p>\ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc758 \uac1c\uc218 T\uac00 \uc8fc\uc5b4\uc9c0\uace0 (1&le;T&le;100) \uac01 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\ub9c8\ub2e4 \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uc815\ubcf4\uc758 \uac1c\uc218 N (1&le;N&le;200)\uc774 \uc8fc\uc5b4\uc9d1\ub2c8\ub2e4. \uadf8\ub9ac\uace0 N\uac1c\uc758 \uc904\uc5d0 \uac78\uccd0\uc11c \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \ubb34\uac8c\uc640 \uc120\uba85\ub3c4 w<sub>i, <\/sub>c<sub>i<\/sub>\uac00 \uc8fc\uc5b4\uc9d1\ub2c8\ub2e4 (0&le;w<sub>i,<\/sub>c<sub>i<\/sub>&le;100).<\/p>\r\n","output":"<p>\uac01 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\ub9c8\ub2e4 \ub2e4\uc774\uc544\ubaac\ub4dc\uc758 \uac00\uce58\uac00 \ub192\uc544\uc9c0\ub294 \ubd80\ubd84\uc5f4\uc911 \ucd5c\uc7a5\uc758 \uac83\uc758 \uae38\uc774\ub97c \uad6c\ud558\uc138\uc694.<\/p>\r\n","hint":"","original":"0","html_title":"0","problem_lang_tcode":"Korean"},{"problem_id":"10571","problem_lang":"1","title":"Diamonds","description":"<p style=\"text-align:center\"><img alt=\"\" src=\"\/upload\/images2\/diamond.png\" style=\"height:72px; width:210px\" \/><\/p>\r\n\r\n<p>A diamond&rsquo;s overall worth is determined by its mass in carats as well as its overall clarity. A large diamond with many imperfections is not worth as much as a smaller, flawless diamond. The overall clarity of a diamond can be described on a scale from 0.0&ndash;10.0 adopted by the American Gem Society, where 0.0 represents a flawless diamond and 10.0 represents an imperfect diamond.<\/p>\r\n\r\n<p>Given a sequence of N diamonds, each with weight, w<sub>i<\/sub>, in carats and clarity, c<sub>i<\/sub>, on the scale described above, find the longest subsequence of diamonds for which the weight and clarity are both becoming strictly more favorable to a buyer.<\/p>\r\n\r\n<p>In the following sequence of diamonds,<\/p>\r\n\r\n<pre>\r\nw<sub>i<\/sub> &nbsp;c<sub>i<\/sub>\r\n1.5 9.0\r\n2.0 2.0\r\n2.5 6.0\r\n3.0 5.0\r\n4.0 2.0\r\n10.0 5.5<\/pre>\r\n\r\n<p>the longest desirable subsequence is<\/p>\r\n\r\n<pre>\r\n1.5 9.0\r\n2.5 6.0\r\n3.0 5.0\r\n4.0 2.0<\/pre>\r\n\r\n<p>because the weights strictly increase while the clarities strictly decrease.<\/p>\r\n","input":"<p>Input begins with a line with a single integer T, 1 &le; T &le; 100, indicating the number of test cases. Each test case begins with a line with a single integer N, 1 &le; N &le; 200, indicating the number of diamonds. Next follow N lines with 2 real numbers w<sub>i<\/sub> and c<sub>i<\/sub>, 0.0 &le; w<sub>i<\/sub>, c<sub>i<\/sub> &le; 10.0, indicating the weight in carats and the clarity of diamond i, respectively.<\/p>\r\n","output":"<p>For each test case, output a single line with the length of the longest desirable subsequence of diamonds.<\/p>\r\n","hint":"","original":"1","html_title":"0","problem_lang_tcode":"English"}]

출처

ICPC > Regionals > North America > Pacific Northwest Regional > 2014 Pacific Northwest Region Programming Contest > Division 2 O번