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문제

청호는 팩맨 게임을 하던 도중, 갑자기 팩맨이 분열하여 2마리가 되는 것을 보았다. 이 2마리의 팩맨은 서로 다른 위치에 있지만, 청호의 조이스틱 하나의 조작에 똑같이 반응하였다. 팩맨을 북쪽으로 가도록 조작하면 2마리의 팩맨이 모두 북쪽으로 이동하고, 동쪽으로 가도록 조작하면 역시 둘 다 동쪽으로 이동하였다. 그러나 팩맨은 자신의 앞에 벽이 있으면 이동하지 않는다.

팩맨이 두 마리이면 좋은 점이 있었다. 단 한 번의 움직임으로 2개의 점을 먹을 수 있는 것이다. 그러나, 청호는 두 마리를 동시 조작하려다 보니 머리가 아프기 시작했다. 또한 두 마리가 각각 유령에게 잡아먹히지 않게 하는 것도 만만치 않았다. 만약 팩맨이 유령과 마주치면 청호는 라이프를 하나 잃게 된다. 청호는 라이프가 5개뿐이고, 두 번째 팩맨은 죽으면 다시 되살아나지 못하기 때문에 두 팩맨을 최대한 빨리 한 장소로 합치기로 결심했다. 과연 이것이 가능할까?

입력

첫 번째 줄에는 테스트 케이스의 개수 T가 주어진다. 각각의 테스트 케이스에는

  • 첫 번째 줄에 M, N (2 ≤ M, N ≤ 50)이 주어진다. M은 미로의 행 개수, N은 미로의 열 개수를 나타낸다.
  • 다음 M개의 줄에 각각 N개의 문자로 미로가 주어진다. 문자는 {P, X, G, .} 중 하나이며 각각
    • P는 팩맨을 의미한다.
    • X는 벽을 의미한다.
    • G는 유령을 의미한다.
    • .은 빈칸을 의미한다.

각 미로에는 정확히 2마리의 팩맨이 존재한다.

출력

각 테스트 케이스에 대해서 정답을 한 줄에 출력한다. 만약 가능할 경우, 팩맨을 조작해야 하는 최소 횟수를 출력한 후, 그 다음에 조작해야 하는 방향을 순서대로 {N, E, S, W}를 사용하여 출력한다. 각각 북쪽, 동쪽, 남쪽, 서쪽을 의미한다. 정답이 여러 개일 경우 아무거나 출력한다. 만약 팩맨을 합치는 것이 불가능하다면 IMPOSSIBLE을 출력한다.

문제를 단순화하기 위해, 유령은 제자리에 가만히 있는다고 가정한다. 또한 팩맨이 화면 끝에서 밖으로 이동하면, 반대편에서 나타난다고 가정한다.

예제 입력 1

3
2 5
.P...
XG.P.
8 8
X...X.X.
X.......
.XXP...X
..X..X..
.PXXXX..
.......X
........
XXXXXXX.
2 2
P.
GP

예제 출력 1

7 WSEESEE
10 EEESSWWWSS
IMPOSSIBLE
[{"problem_id":"11451","problem_lang":"0","title":"\ud329\ub9e8","description":"<p>\uccad\ud638\ub294 \ud329\ub9e8 \uac8c\uc784\uc744 \ud558\ub358 \ub3c4\uc911, \uac11\uc790\uae30 \ud329\ub9e8\uc774 \ubd84\uc5f4\ud558\uc5ec 2\ub9c8\ub9ac\uac00 \ub418\ub294 \uac83\uc744 \ubcf4\uc558\ub2e4. \uc774 2\ub9c8\ub9ac\uc758 \ud329\ub9e8\uc740 \uc11c\ub85c \ub2e4\ub978 \uc704\uce58\uc5d0 \uc788\uc9c0\ub9cc, \uccad\ud638\uc758 \uc870\uc774\uc2a4\ud2f1 \ud558\ub098\uc758 \uc870\uc791\uc5d0 \ub611\uac19\uc774 \ubc18\uc751\ud558\uc600\ub2e4. \ud329\ub9e8\uc744 \ubd81\ucabd\uc73c\ub85c \uac00\ub3c4\ub85d \uc870\uc791\ud558\uba74 2\ub9c8\ub9ac\uc758 \ud329\ub9e8\uc774 \ubaa8\ub450 \ubd81\ucabd\uc73c\ub85c \uc774\ub3d9\ud558\uace0, \ub3d9\ucabd\uc73c\ub85c \uac00\ub3c4\ub85d \uc870\uc791\ud558\uba74 \uc5ed\uc2dc \ub458 \ub2e4 \ub3d9\ucabd\uc73c\ub85c \uc774\ub3d9\ud558\uc600\ub2e4. \uadf8\ub7ec\ub098 \ud329\ub9e8\uc740 \uc790\uc2e0\uc758 \uc55e\uc5d0 \ubcbd\uc774 \uc788\uc73c\uba74 \uc774\ub3d9\ud558\uc9c0 \uc54a\ub294\ub2e4.<\/p>\r\n\r\n<p>\ud329\ub9e8\uc774 \ub450 \ub9c8\ub9ac\uc774\uba74 \uc88b\uc740 \uc810\uc774 \uc788\uc5c8\ub2e4. \ub2e8 \ud55c \ubc88\uc758 \uc6c0\uc9c1\uc784\uc73c\ub85c 2\uac1c\uc758 \uc810\uc744 \uba39\uc744 \uc218 \uc788\ub294 \uac83\uc774\ub2e4. \uadf8\ub7ec\ub098, \uccad\ud638\ub294 \ub450 \ub9c8\ub9ac\ub97c \ub3d9\uc2dc \uc870\uc791\ud558\ub824\ub2e4 \ubcf4\ub2c8 \uba38\ub9ac\uac00 \uc544\ud504\uae30 \uc2dc\uc791\ud588\ub2e4. \ub610\ud55c \ub450 \ub9c8\ub9ac\uac00 \uac01\uac01 \uc720\ub839\uc5d0\uac8c \uc7a1\uc544\uba39\ud788\uc9c0 \uc54a\uac8c \ud558\ub294 \uac83\ub3c4 \ub9cc\ub9cc\uce58 \uc54a\uc558\ub2e4. \ub9cc\uc57d \ud329\ub9e8\uc774 \uc720\ub839\uacfc \ub9c8\uc8fc\uce58\uba74 \uccad\ud638\ub294 \ub77c\uc774\ud504\ub97c \ud558\ub098 \uc783\uac8c \ub41c\ub2e4. \uccad\ud638\ub294 \ub77c\uc774\ud504\uac00 5\uac1c\ubfd0\uc774\uace0, \ub450 \ubc88\uc9f8 \ud329\ub9e8\uc740 \uc8fd\uc73c\uba74 \ub2e4\uc2dc \ub418\uc0b4\uc544\ub098\uc9c0 \ubabb\ud558\uae30 \ub54c\ubb38\uc5d0 \ub450 \ud329\ub9e8\uc744 \ucd5c\ub300\ud55c \ube68\ub9ac \ud55c \uc7a5\uc18c\ub85c \ud569\uce58\uae30\ub85c \uacb0\uc2ec\ud588\ub2e4. \uacfc\uc5f0 \uc774\uac83\uc774 \uac00\ub2a5\ud560\uae4c?<\/p>\r\n","input":"<p>\uccab \ubc88\uc9f8 \uc904\uc5d0\ub294 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc758 \uac1c\uc218 T\uac00 \uc8fc\uc5b4\uc9c4\ub2e4. \uac01\uac01\uc758 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc5d0\ub294<\/p>\r\n\r\n<ul>\r\n\t<li>\uccab \ubc88\uc9f8 \uc904\uc5d0 M, N (2 &le; M, N &le; 50)\uc774 \uc8fc\uc5b4\uc9c4\ub2e4. M\uc740 \ubbf8\ub85c\uc758 \ud589 \uac1c\uc218, N\uc740 \ubbf8\ub85c\uc758 \uc5f4 \uac1c\uc218\ub97c \ub098\ud0c0\ub0b8\ub2e4.<\/li>\r\n\t<li>\ub2e4\uc74c M\uac1c\uc758 \uc904\uc5d0 \uac01\uac01 N\uac1c\uc758 \ubb38\uc790\ub85c \ubbf8\ub85c\uac00 \uc8fc\uc5b4\uc9c4\ub2e4. \ubb38\uc790\ub294 {P, X, G, .} \uc911 \ud558\ub098\uc774\uba70 \uac01\uac01\r\n\t<ul>\r\n\t\t<li>P\ub294 \ud329\ub9e8\uc744 \uc758\ubbf8\ud55c\ub2e4.<\/li>\r\n\t\t<li>X\ub294 \ubcbd\uc744 \uc758\ubbf8\ud55c\ub2e4.<\/li>\r\n\t\t<li>G\ub294 \uc720\ub839\uc744 \uc758\ubbf8\ud55c\ub2e4.<\/li>\r\n\t\t<li>.\uc740 \ube48\uce78\uc744 \uc758\ubbf8\ud55c\ub2e4.<\/li>\r\n\t<\/ul>\r\n\t<\/li>\r\n<\/ul>\r\n\r\n<p>\uac01 \ubbf8\ub85c\uc5d0\ub294 \uc815\ud655\ud788 2\ub9c8\ub9ac\uc758 \ud329\ub9e8\uc774 \uc874\uc7ac\ud55c\ub2e4.<\/p>\r\n","output":"<p>\uac01 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc5d0 \ub300\ud574\uc11c \uc815\ub2f5\uc744 \ud55c \uc904\uc5d0 \ucd9c\ub825\ud55c\ub2e4. \ub9cc\uc57d \uac00\ub2a5\ud560 \uacbd\uc6b0, \ud329\ub9e8\uc744 \uc870\uc791\ud574\uc57c \ud558\ub294 \ucd5c\uc18c \ud69f\uc218\ub97c \ucd9c\ub825\ud55c \ud6c4, \uadf8 \ub2e4\uc74c\uc5d0 \uc870\uc791\ud574\uc57c \ud558\ub294 \ubc29\ud5a5\uc744 \uc21c\uc11c\ub300\ub85c {N, E, S, W}\ub97c \uc0ac\uc6a9\ud558\uc5ec \ucd9c\ub825\ud55c\ub2e4. \uac01\uac01 \ubd81\ucabd, \ub3d9\ucabd, \ub0a8\ucabd, \uc11c\ucabd\uc744 \uc758\ubbf8\ud55c\ub2e4. \uc815\ub2f5\uc774 \uc5ec\ub7ec \uac1c\uc77c \uacbd\uc6b0 \uc544\ubb34\uac70\ub098 \ucd9c\ub825\ud55c\ub2e4. \ub9cc\uc57d \ud329\ub9e8\uc744 \ud569\uce58\ub294 \uac83\uc774 \ubd88\uac00\ub2a5\ud558\ub2e4\uba74 IMPOSSIBLE\uc744 \ucd9c\ub825\ud55c\ub2e4.<\/p>\r\n\r\n<p>\ubb38\uc81c\ub97c \ub2e8\uc21c\ud654\ud558\uae30 \uc704\ud574, \uc720\ub839\uc740 \uc81c\uc790\ub9ac\uc5d0 \uac00\ub9cc\ud788 \uc788\ub294\ub2e4\uace0 \uac00\uc815\ud55c\ub2e4. \ub610\ud55c \ud329\ub9e8\uc774 \ud654\uba74 \ub05d\uc5d0\uc11c \ubc16\uc73c\ub85c \uc774\ub3d9\ud558\uba74, \ubc18\ub300\ud3b8\uc5d0\uc11c \ub098\ud0c0\ub09c\ub2e4\uace0 \uac00\uc815\ud55c\ub2e4.<\/p>\r\n","hint":"","original":"0","html_title":"0","problem_lang_tcode":"Korean"},{"problem_id":"11451","problem_lang":"1","title":"Pac-Man","description":"<p>While playing some old-school Pac-Man game, you suddenly discover that Pac-Man has magically doubled itself. There are two Pac-Man characters in the maze, at different positions, and both respond to your single joystick. When you move the joystick north, they both go north, when you move it east, they both go east, et cetera. However, the characters cannot move into (or through) a wall. If there is a wall to the north of a Pac-Man character, and you move the joystick north, then this particular character does not move.<\/p>\r\n\r\n<p>On the one hand, it is beneficial to have two PacMan characters: they can eat two pac-dots in one move.&nbsp;On the other hand, you get terribly confused from looking at two characters all the time. And it is much harder to stay away from the ghosts (the enemies in the game) with two characters than with one. If any character bumps into a ghost (or the other way round), you lose a life. Because you have only five lives, and the second character did not get you an additional life, you decide it would be best if you could move the two Pac-Man characters onto the same position. But is that possible?<\/p>\r\n","input":"<p>The input starts with a line containing an integer T, the number of test cases. Then for each test case:<\/p>\r\n\r\n<ul>\r\n\t<li>A line containing two space-separated integers M and N satisfying 2 &le; M, N &le; 50: the dimensions of the maze.<\/li>\r\n\t<li>M lines describing the maze, each containing N characters from {P, X, G, .}, where\r\n\t<ul>\r\n\t\t<li>P indicates a Pac-Man character,<\/li>\r\n\t\t<li>X indicates a wall,<\/li>\r\n\t\t<li>G indicates a ghost,<\/li>\r\n\t\t<li>. indicates an empty position.<\/li>\r\n\t<\/ul>\r\n\t<\/li>\r\n<\/ul>\r\n\r\n<p>There are exactly two occurrences of P in the maze<\/p>\r\n","output":"<p>For each test case, output a single line containing a positive integer D, a space and a sequence of D characters from {N, E, S, W} (North, East, South, West), indicating a shortest sequence of joystick moves that brings the two Pac-Man characters at the same position, without bumping into a ghost with either of the characters. If there are multiple solutions, output one. If there is no such sequence of moves at all, then output the string IMPOSSIBLE.<\/p>\r\n\r\n<p>For simplicitly, we assume that the ghosts in the maze do not move. We further assume that a Pac-Man character can step in one move from one edge of the maze to the corresponding position at the opposite edge of the maze.<\/p>\r\n","hint":"","original":"1","html_title":"0","problem_lang_tcode":"English"}]

출처

ICPC > Regionals > Europe > Northwestern European Regional Contest > Benelux Algorithm Programming Contest > BAPC 2015 Preliminaries G번

  • 문제를 번역한 사람: kks227
  • 문제를 만든 사람: Rudy van Vliet