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## 문제

Given a permutation π of integers 1 through n, an interval in π is a consecutive subsequence consisting of consecutive numbers. More precisely, for indices a and b where 1 ≤ a ≤ b ≤ n, the subsequence πab = (πa, πa+1, . . . , πb) is an interval if sorting it would yield a sequence of consecutive integers. For example, in permutation π = (3, 1, 7, 5, 6, 4, 2), the subsequence π36 is an interval (it contains the numbers 4 through 7) while π13 is not.

For a subsequence πxy its intrinsic interval is any interval πab that contains the given subsequence (a ≤ x ≤ y ≤ b) and that is, additionally, as short as possible. Of course, the length of an interval is defined as the number of elements it contains.

Given a permutation π and m of its subsequences, find some intrinsic interval for each subsequence.

## 입력

The first line contains an integer n (1 ≤ n ≤ 100 000) — the size of the permutation π. The following line contains n different integers π1, π2, . . . , πn (1 ≤ πj ≤ n) — the permutation itself.

The following line contains an integer m (1 ≤ m ≤ 100 000) — the number of subsequences. The j-th of the following m lines contains integers xj and yj (1 ≤ xj ≤ yj ≤ n) — the endpoints of the j-th subsequence.

## 출력

Output m lines. The j-th line should contain two integers aj and bj where 1 ≤ aj ≤ bj ≤ n — the endpoints of some intrinsic interval of the j-th subsequence πxjyj.

## 예제 입력 1

7
3 1 7 5 6 4 2
3
3 6
7 7
1 3


## 예제 출력 1

3 6
7 7
1 7


## 예제 입력 2

10
2 1 4 3 5 6 7 10 8 9
5
2 3
3 7
4 7
4 8
7 8


## 예제 출력 2

1 4
3 7
3 7
3 10
7 10