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## 문제

There is an array a of length n, consisting of distinct integers. It is guaranteed that every element of the array is a positive integer less than or equal to 109. You have to find out the values of all the elements of it.

To do so, you can make up to 30 queries of the following two types:

• “1 i” (1 ≤ i ≤ n) — ask the value of ai
• “2 k i1, i2, . . . , ik” (2 ≤ k ≤ n, 1 ≤ ij ≤ n, all ij must be distinct) — the number k and k positions in the array. As the answer to this query you will receive k·(k−1)/2 integers — |aic − aid| for every c < d. In other words, you will receive k·(k−1)/2 absolute values of differences between all pairs of elements that are on positions i1, i2, . . . , ik. Note that the answer on query 2 is randomly shuffled.

Once you know the answer, print it using the following query:

• “3 a1, a2, . . . , an” (1 ≤ ai ≤ 109) — the elements of the array a. After this query, your program must terminate. This query doesn’t count (i.e. you can make up to 30 queries of either of the first two types plus 1 query of the third type).

## 프로토콜

At the beginning, your program should read one integer n (1 ≤ n ≤ 250) — the number of elements.

In order to make a query of the first type, print “1 i” (1 ≤ i ≤ n). After this query, read one integer — the value of ai.

In order to make a query of the second type, print “2 k” (2 ≤ k ≤ n). Then in the same line print k space-separated distinct integers — i1, i2, . . . , ik, (1 ≤ ij ≤ n). After this query read k·(k−1)/2 integers — |aic − aid| for every c < d. These values will be given in random order.

Once you know the answer, print “3”. Then in the same line, print n space-separated integers — a1, a2, . . . , an (1 ≤ ai ≤ 109). Your program must terminate after this query.

If for either of two first queries you get one number −1 as the answer, then it means that you made more queries than allowed, or made an invalid query. Your program should immediately terminate (for example, by calling exit(0)). You will receive “Wrong Answer”. If you ignore this, you can get other verdicts since your program will continue to read from a closed stream.

After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Wall time-limit exceeded. To do this, use:

• fflush(stdout) or cout.flush() in C++;
• System.out.flush() in Java;
• stdout.flush() in Python.

Precisely follow this format of interaction

## 예제 입력 1

3

1

2

4 3 1



## 예제 출력 1


1 1

1 2

2 3 1 2 3

3 1 2 5


## 힌트

In the first query of type 1, we ask the value of a1 and receive 1 as the answer.

In the second query of type 2, we ask the value of a2 and receive 2 as the answer.

In the query of type 2, we ask all the possible differences between the elements of array with indexes 1, 2 and 3. And we get array 4, 3, 1 as the result. We know that the array contains values |a1−a2|, |a1−a3|, |a2−a3|. Since we already know that |a2 − a1| = 1, one of the following is true: |a1 − a3| = 3 and |a2 − a3| = 4 or |a2 − a3| = 3 and |a1 − a3| = 4. The only case that is possible, taking into account the constraints of the problem, is when |a1 − a3| = 4 and |a2 − a3| = 3 with a3 = 5.

Since we know the values of all the elements of the array, we print them in the last query.

## 채점 및 기타 정보

• 예제는 채점하지 않는다.