시간 제한메모리 제한제출정답맞힌 사람정답 비율
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문제

Alice와 Bob은 "정수 그래프"를 이용한 놀이를 즐겨한다.

"정수 그래프"는 노드와 간선의 수가 무한한 방향성이 없는 그래프인고, 다음과 같이 정의한다.

  • 노드: 모든 양의 정수 $z$에 대응되는 고유한 노드가 존재한다. 따라서, 임의의 노드는 해당 노드의 정수로 나타낼 수 있다.
  • 간선: 어떤 노드 $x$와 $y$가 아래 조건 중 하나를 충족하면 둘 사이에 간선이 존재한다.
    1. $x > y$ 라면: $x$의 $1$이 아닌 약수 중 가장 작은 수가 $d$일 때, $x/d = y$라면 두 노드 사이에 간선이 존재한다. 해당 간선의 길이는 $d$이다.
    2. $x < y$ 라면: $y$의 $1$이 아닌 약수 중 가장 작은 수가 $d$일 때, $y/d = x$라면 두 노드 사이에 간선이 존재한다. 해당 간선의 길이는 $d$이다.
  • 일반적인 그래프와 마찬가지로 최단 경로를 정의하며, $dist(x, y)$는 두 노드 $x$, $y$ 사이의 최단 경로의 길이를 나타낸다. 이때 길이는 해당 최단 경로에 속한 간선의 길이의 총합이다.

예를 들어, 아래 그림은 "정수 그래프"의 일부를 보여 준다. 가령 노드 $10$과 $20$사이에는 길이 $2$인 간선이 존재하고, 노드 $25$와 $5$사이에는 길이 $5$인 간선이 존재한다.

두 아이는 정수 그래프를 이용해서 아래와 같은 놀이를 하기로 했다:

  • 먼저 Alice가 $n$개의 양의 정수 $v_1, v_2, \dots, v_n$를 고른다 (같은 정수를 여러 번 고를 수도 있다). 그리고 $D$를 다음과 같이 정의한다: \(D = \sum_{1 \le i \lt j \le n} dist(v_i, v_j)\) 즉, D값은 Alice가 고른 정수들 각 쌍에 대하여 그에 해당하는 두 노드 사이의 최단 경로 길이의 총합이다.
  • 다음으로, Bob이 $n$개의 정수 중 하나를 빼고, 나머지 $n-1$개의 정수에 대하여 마찬가지로 $D$값을 새로 계산한다. 즉, $1$이상 $n$이하의 정수 중 $k$번째 정수를 빼고, 새로 계산할 $D$값을 $E(k)$라고 한다면: \( E(k) = \sum_{1 \le i \lt j \le n, i \ne k, j \ne k} dist(v_i, v_j) \)가 된다. 이때 Bob은 $E(k)$값이 최소가 되도록 하고 싶다.

예를 들어 Alice가 $v_1 = 10$, $v_2 = 15$, $v_3 = 25$를 골랐을 경우를 살펴보자.

  • $dist(v_1, v_2) = 5$, $dist(v_2, v_3) = 8$, $dist(v_3, v_1) = 7$이 되어 $D = 5+8+7 = 20$이다.
  • Bob이 $v_1$을 제거하면 $v_2, v_3$만 남게 되어 $E(1) = 8$이다.
  • Bob이 $v_2$을 제거하면 $v_1, v_3$만 남게 되어 $E(2) = 7$이다.
  • Bob이 $v_3$을 제거하면 $v_1, v_2$만 남게 되어 $E(3) = 5$이다.

입력으로 Alice가 선택한 $n$개의 정수가 주어졌을 때, Bob이 달성할 수 있는 $E(k)$의 최소값을 구해보자.

입력

첫 줄에 테스트 케이스의 수 $T$가 주어진다.

각 테스트 케이스의 입력은 두 줄에 걸쳐 주어진다. 첫 줄에 $n$이 주어지고 둘째 줄에 Alice가 고른 $n$개의 정수 $v_1, v_2, \dots, v_n$이 공백으로 구분되어 주어진다.

출력

각 테스트 케이스의 정답을 각 줄에 출력한다.

서브태스크 1 (10점)

  • $1 ≤ T ≤ 10$
  • $1 ≤ n ≤ 500$
  • $1 ≤ v_1, v_2, \dots, v_n ≤ 1\,000\,000$

서브태스크 2 (20점)

  • $1 ≤ T ≤ 10$
  • $1 ≤ n ≤ 100\,000$
  • $1 ≤ v_1, v_2, \dots, v_n ≤ 1\,000\,000$

예제 입력 1

6
3
10 15 25
4
24 36 20 30
6
10 20 30 30 20 10
4
12 18 24 36
8
10 10 20 20 20 30 30 30
4
1 1 1 2

예제 출력 1

5
46
40
22
94
0
  • 예제 1: $25$를 빼면 $10$과 $15$사이 거리가 $5$이므로 $E(k)$값이 최소가 된다.
  • 예제 2: $36$을 빼는 것이 최선이다.
  • 예제 3: 두 개의 $30$중 하나를 빼면 된다.
  • 예제 4: $24$를 빼거나 $36$을 빼면 된다.
  • 예제 6: $2$를 빼는 것이 최선이다.
[{"problem_id":"24433","problem_lang":"0","title":"\uc815\uc218 \uadf8\ub798\ud504","description":"<p>Alice\uc640 Bob\uc740 &quot;\uc815\uc218 \uadf8\ub798\ud504&quot;\ub97c \uc774\uc6a9\ud55c \ub180\uc774\ub97c \uc990\uaca8\ud55c\ub2e4.<\/p>\r\n\r\n<p>&quot;\uc815\uc218 \uadf8\ub798\ud504&quot;\ub294 \ub178\ub4dc\uc640 \uac04\uc120\uc758 \uc218\uac00 \ubb34\ud55c\ud55c \ubc29\ud5a5\uc131\uc774 \uc5c6\ub294 \uadf8\ub798\ud504\uc778\uace0, \ub2e4\uc74c\uacfc \uac19\uc774 \uc815\uc758\ud55c\ub2e4.<\/p>\r\n\r\n<ul>\r\n\t<li>\ub178\ub4dc: \ubaa8\ub4e0 \uc591\uc758 \uc815\uc218 $z$\uc5d0 \ub300\uc751\ub418\ub294 \uace0\uc720\ud55c \ub178\ub4dc\uac00 \uc874\uc7ac\ud55c\ub2e4. \ub530\ub77c\uc11c, \uc784\uc758\uc758 \ub178\ub4dc\ub294 \ud574\ub2f9 \ub178\ub4dc\uc758 \uc815\uc218\ub85c \ub098\ud0c0\ub0bc \uc218 \uc788\ub2e4.<\/li>\r\n\t<li>\uac04\uc120: \uc5b4\ub5a4 \ub178\ub4dc $x$\uc640 $y$\uac00 \uc544\ub798 \uc870\uac74 \uc911 \ud558\ub098\ub97c \ucda9\uc871\ud558\uba74 \ub458 \uc0ac\uc774\uc5d0 \uac04\uc120\uc774 \uc874\uc7ac\ud55c\ub2e4.\r\n\t<ol>\r\n\t\t<li>$x &gt; y$ \ub77c\uba74: $x$\uc758 $1$\uc774 \uc544\ub2cc \uc57d\uc218 \uc911 \uac00\uc7a5 \uc791\uc740 \uc218\uac00 $d$\uc77c \ub54c, $x\/d = y$\ub77c\uba74 \ub450 \ub178\ub4dc \uc0ac\uc774\uc5d0 \uac04\uc120\uc774 \uc874\uc7ac\ud55c\ub2e4. \ud574\ub2f9 \uac04\uc120\uc758 \uae38\uc774\ub294 $d$\uc774\ub2e4.<\/li>\r\n\t\t<li>$x &lt; y$ \ub77c\uba74: $y$\uc758 $1$\uc774 \uc544\ub2cc \uc57d\uc218 \uc911 \uac00\uc7a5 \uc791\uc740 \uc218\uac00 $d$\uc77c \ub54c, $y\/d = x$\ub77c\uba74 \ub450 \ub178\ub4dc \uc0ac\uc774\uc5d0 \uac04\uc120\uc774 \uc874\uc7ac\ud55c\ub2e4. \ud574\ub2f9 \uac04\uc120\uc758 \uae38\uc774\ub294 $d$\uc774\ub2e4.<\/li>\r\n\t<\/ol>\r\n\t<\/li>\r\n\t<li>\uc77c\ubc18\uc801\uc778 \uadf8\ub798\ud504\uc640 \ub9c8\ucc2c\uac00\uc9c0\ub85c \ucd5c\ub2e8 \uacbd\ub85c\ub97c \uc815\uc758\ud558\uba70, $dist(x, y)$\ub294 \ub450 \ub178\ub4dc $x$, $y$ \uc0ac\uc774\uc758 \ucd5c\ub2e8 \uacbd\ub85c\uc758 \uae38\uc774\ub97c \ub098\ud0c0\ub0b8\ub2e4. \uc774\ub54c \uae38\uc774\ub294 \ud574\ub2f9 \ucd5c\ub2e8 \uacbd\ub85c\uc5d0 \uc18d\ud55c \uac04\uc120\uc758 \uae38\uc774\uc758 \ucd1d\ud569\uc774\ub2e4.<\/li>\r\n<\/ul>\r\n\r\n<p>\uc608\ub97c \ub4e4\uc5b4, \uc544\ub798 \uadf8\ub9bc\uc740 &quot;\uc815\uc218 \uadf8\ub798\ud504&quot;\uc758 \uc77c\ubd80\ub97c \ubcf4\uc5ec \uc900\ub2e4. \uac00\ub839 \ub178\ub4dc $10$\uacfc $20$\uc0ac\uc774\uc5d0\ub294 \uae38\uc774 $2$\uc778 \uac04\uc120\uc774 \uc874\uc7ac\ud558\uace0, \ub178\ub4dc $25$\uc640 $5$\uc0ac\uc774\uc5d0\ub294 \uae38\uc774 $5$\uc778 \uac04\uc120\uc774 \uc874\uc7ac\ud55c\ub2e4.<\/p>\r\n\r\n<p style=\"text-align: center;\"><img alt=\"\" src=\"https:\/\/upload.acmicpc.net\/b0c47370-c08c-42c2-8aa2-41668b2d3114\/-\/preview\/\" style=\"height: 263px; width: 300px;\" \/><\/p>\r\n\r\n<p>\ub450 \uc544\uc774\ub294 \uc815\uc218 \uadf8\ub798\ud504\ub97c \uc774\uc6a9\ud574\uc11c \uc544\ub798\uc640 \uac19\uc740 \ub180\uc774\ub97c \ud558\uae30\ub85c \ud588\ub2e4:<\/p>\r\n\r\n<ul>\r\n\t<li>\uba3c\uc800 Alice\uac00 $n$\uac1c\uc758 \uc591\uc758 \uc815\uc218 $v_1, v_2, \\dots, v_n$\ub97c \uace0\ub978\ub2e4 (\uac19\uc740 \uc815\uc218\ub97c \uc5ec\ub7ec \ubc88 \uace0\ub97c \uc218\ub3c4 \uc788\ub2e4). \uadf8\ub9ac\uace0 $D$\ub97c \ub2e4\uc74c\uacfc \uac19\uc774 \uc815\uc758\ud55c\ub2e4: \\(D = \\sum_{1 \\le i \\lt j \\le n} dist(v_i, v_j)\\) \uc989, D\uac12\uc740 Alice\uac00 \uace0\ub978 \uc815\uc218\ub4e4 \uac01 \uc30d\uc5d0 \ub300\ud558\uc5ec \uadf8\uc5d0 \ud574\ub2f9\ud558\ub294 \ub450 \ub178\ub4dc \uc0ac\uc774\uc758 \ucd5c\ub2e8 \uacbd\ub85c \uae38\uc774\uc758 \ucd1d\ud569\uc774\ub2e4.<\/li>\r\n\t<li>\ub2e4\uc74c\uc73c\ub85c, Bob\uc774 $n$\uac1c\uc758 \uc815\uc218 \uc911 \ud558\ub098\ub97c \ube7c\uace0, \ub098\uba38\uc9c0 $n-1$\uac1c\uc758 \uc815\uc218\uc5d0 \ub300\ud558\uc5ec \ub9c8\ucc2c\uac00\uc9c0\ub85c $D$\uac12\uc744 \uc0c8\ub85c \uacc4\uc0b0\ud55c\ub2e4. \uc989, $1$\uc774\uc0c1 $n$\uc774\ud558\uc758 \uc815\uc218 \uc911 $k$\ubc88\uc9f8 \uc815\uc218\ub97c \ube7c\uace0, \uc0c8\ub85c \uacc4\uc0b0\ud560 $D$\uac12\uc744 $E(k)$\ub77c\uace0 \ud55c\ub2e4\uba74: \\( E(k) = \\sum_{1 \\le i \\lt j \\le n, i \\ne k, j \\ne k} dist(v_i, v_j) \\)\uac00 \ub41c\ub2e4. \uc774\ub54c Bob\uc740 $E(k)$\uac12\uc774 \ucd5c\uc18c\uac00 \ub418\ub3c4\ub85d \ud558\uace0 \uc2f6\ub2e4.<\/li>\r\n<\/ul>\r\n\r\n<p>\uc608\ub97c \ub4e4\uc5b4 Alice\uac00 $v_1 = 10$, $v_2 = 15$, $v_3 = 25$\ub97c \uace8\ub790\uc744 \uacbd\uc6b0\ub97c \uc0b4\ud3b4\ubcf4\uc790.<\/p>\r\n\r\n<ul>\r\n\t<li>$dist(v_1, v_2) = 5$, $dist(v_2, v_3) = 8$, $dist(v_3, v_1) = 7$\uc774 \ub418\uc5b4 $D = 5+8+7 = 20$\uc774\ub2e4.<\/li>\r\n\t<li>Bob\uc774 $v_1$\uc744 \uc81c\uac70\ud558\uba74 $v_2, v_3$\ub9cc \ub0a8\uac8c \ub418\uc5b4 $E(1) = 8$\uc774\ub2e4.<\/li>\r\n\t<li>Bob\uc774 $v_2$\uc744 \uc81c\uac70\ud558\uba74 $v_1, v_3$\ub9cc \ub0a8\uac8c \ub418\uc5b4 $E(2) = 7$\uc774\ub2e4.<\/li>\r\n\t<li>Bob\uc774 $v_3$\uc744 \uc81c\uac70\ud558\uba74 $v_1, v_2$\ub9cc \ub0a8\uac8c \ub418\uc5b4 $E(3) = 5$\uc774\ub2e4.<\/li>\r\n<\/ul>\r\n\r\n<p>\uc785\ub825\uc73c\ub85c Alice\uac00 \uc120\ud0dd\ud55c $n$\uac1c\uc758 \uc815\uc218\uac00 \uc8fc\uc5b4\uc84c\uc744 \ub54c, Bob\uc774 \ub2ec\uc131\ud560 \uc218 \uc788\ub294 $E(k)$\uc758 \ucd5c\uc18c\uac12\uc744 \uad6c\ud574\ubcf4\uc790.<\/p>\r\n","input":"<p>\uccab \uc904\uc5d0 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc758 \uc218 $T$\uac00 \uc8fc\uc5b4\uc9c4\ub2e4.<\/p>\r\n\r\n<p>\uac01 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc758 \uc785\ub825\uc740 \ub450 \uc904\uc5d0 \uac78\uccd0 \uc8fc\uc5b4\uc9c4\ub2e4. \uccab \uc904\uc5d0 $n$\uc774 \uc8fc\uc5b4\uc9c0\uace0 \ub458\uc9f8 \uc904\uc5d0 Alice\uac00 \uace0\ub978 $n$\uac1c\uc758 \uc815\uc218 $v_1, v_2, \\dots, v_n$\uc774 \uacf5\ubc31\uc73c\ub85c \uad6c\ubd84\ub418\uc5b4 \uc8fc\uc5b4\uc9c4\ub2e4.<\/p>\r\n","output":"<p>\uac01 \ud14c\uc2a4\ud2b8 \ucf00\uc774\uc2a4\uc758 \uc815\ub2f5\uc744 \uac01 \uc904\uc5d0 \ucd9c\ub825\ud55c\ub2e4.<\/p>\r\n","hint":"","original":"1","html_title":"0","problem_lang_tcode":"Korean","subtask1":"<ul>\r\n\t<li>$1 &le; T &le; 10$<\/li>\r\n\t<li>$1 &le; n &le; 500$<\/li>\r\n\t<li>$1 &le; v_1, v_2, \\dots, v_n &le; 1\\,000\\,000$<\/li>\r\n<\/ul>\r\n","subtask2":"<ul>\r\n\t<li>$1 &le; T &le; 10$<\/li>\r\n\t<li>$1 &le; n &le; 100\\,000$<\/li>\r\n\t<li>$1 &le; v_1, v_2, \\dots, v_n &le; 1\\,000\\,000$<\/li>\r\n<\/ul>\r\n","sample_explain_1":"<ul>\r\n\t<li>\uc608\uc81c 1: $25$\ub97c \ube7c\uba74 $10$\uacfc $15$\uc0ac\uc774 \uac70\ub9ac\uac00 $5$\uc774\ubbc0\ub85c $E(k)$\uac12\uc774 \ucd5c\uc18c\uac00 \ub41c\ub2e4.<\/li>\r\n\t<li>\uc608\uc81c 2: $36$\uc744 \ube7c\ub294 \uac83\uc774 \ucd5c\uc120\uc774\ub2e4.<\/li>\r\n\t<li>\uc608\uc81c 3: \ub450 \uac1c\uc758 $30$\uc911 \ud558\ub098\ub97c \ube7c\uba74 \ub41c\ub2e4.<\/li>\r\n\t<li>\uc608\uc81c 4: $24$\ub97c \ube7c\uac70\ub098 $36$\uc744 \ube7c\uba74 \ub41c\ub2e4.<\/li>\r\n\t<li>\uc608\uc81c 6: $2$\ub97c \ube7c\ub294 \uac83\uc774 \ucd5c\uc120\uc774\ub2e4.<\/li>\r\n<\/ul>\r\n"},{"problem_id":"24433","problem_lang":"1","title":"Integer Graph","description":"<p>Alice and Bob love playing games using the &quot;Integer Graph.&quot;<\/p>\r\n\r\n<p>The Integer Graph is an undirected graph of infinite size, which is defined as follows:<\/p>\r\n\r\n<ul>\r\n\t<li>Nodes: For every positive integer, there exists a unique, corresponding node in the graph. Hence, a node can be represented by a positive integer.<\/li>\r\n\t<li>Edges: If two nodes $x$ and $y$ satisfy the following condition, then there exists an edge between them:\r\n\t<ol>\r\n\t\t<li>If $x &gt; y$: If $d$ is the smallest divisor of $x$ greater than $1$ and $x\/d = y$, then there exists an edge between $x$ and $y$ whose length is $d$.<\/li>\r\n\t\t<li>If $x &lt; y$: If $d$ is the smallest divisor of $y$ greater than $1$ and $y\/d = x$, then&nbsp;there exists an edge between $x$ and $y$ whose length is $d$.<\/li>\r\n\t<\/ol>\r\n\t<\/li>\r\n\t<li>A shortest path is defined in the standard way, and $dist(x, y)$ denotes the length of a shortest path between $x$ and $y$ (which is the sum of the lengths of the edges in any shortest path).<\/li>\r\n<\/ul>\r\n\r\n<p>For instance, the following image illustrates a part of the Integer Graph. Between $10$ and $20$, there exists an edge of length $2$ and between $25$ and $5$ an edge of length $5$.<\/p>\r\n\r\n<p style=\"text-align: center;\"><img alt=\"\" src=\"https:\/\/upload.acmicpc.net\/b0c47370-c08c-42c2-8aa2-41668b2d3114\/-\/preview\/\" style=\"width: 300px;\" \/><\/p>\r\n\r\n<p>Two kids will play the following game:<\/p>\r\n\r\n<ul>\r\n\t<li>First, Alice will pick $n$ positive integers&nbsp;$v_1, v_2, \\dots, v_n$ (the same number may be picked multiple times). Then, $D$ is defined as follows: \\(D = \\sum_{1 \\le i \\lt j \\le n} dist(v_i, v_j)\\) That is, $D$ is the sum of shortest path distances over all pairs of numbers that Alice picked.<\/li>\r\n\t<li>Next, Bob will discard one of the $n$ integers, and will re-calculate the value of $D$ using the remaining $n-1$ integers. That is, if Bob were to discard the $k$-th integer, then the new value for $D$ (which we call $E(k)$) will be: \\( E(k) = \\sum_{1 \\le i \\lt j \\le n, i \\ne k, j \\ne k} dist(v_i, v_j) \\). Bob wishes to find $k$ that yields smallest $E(k)$ value.<\/li>\r\n<\/ul>\r\n\r\n<p>For instance, suppose that&nbsp;Alice chooses&nbsp;$v_1 = 10$, $v_2 = 15$, $v_3 = 25$:<\/p>\r\n\r\n<ul>\r\n\t<li>$dist(v_1, v_2) = 5$, $dist(v_2, v_3) = 8$, $dist(v_3, v_1) = 7$, and thus $D = 5+8+7 = 20$.<\/li>\r\n\t<li>If Bob discards $v_1$, then using $v_2$ and $v_3$, he obtains $E(1) = 8$.<\/li>\r\n\t<li>If Bob discards $v_2$, then using $v_1$ and $v_3$, he obtains $E(2) = 7$.<\/li>\r\n\t<li>If Bob discards $v_3$, then using $v_1$ and $v_2$, he obtains $E(3) = 5$.<\/li>\r\n<\/ul>\r\n\r\n<p>Given $n$ positive integers that Alice chose, compute the smallest $E(k)$ value that Bob can achieve.<\/p>\r\n","input":"<p>The first line of the input will contain $T$, the number of test cases.<\/p>\r\n\r\n<p>Each test case will be given by two lines. The first line will contain $n$ and the second line will contain $n$ integers $v_1, v_2, \\dots, v_n$ separated by whitespace.<\/p>\r\n","output":"<p>Output each test case&#39;s answer in each separate line.<\/p>\r\n","hint":"","original":"0","html_title":"0","problem_lang_tcode":"English","subtask1":"<ul>\r\n\t<li>$1 &le; T &le; 10$<\/li>\r\n\t<li>$1 &le; n &le; 500$<\/li>\r\n\t<li>$1 &le; v_1, v_2, \\dots, v_n &le; 1\\,000\\,000$<\/li>\r\n<\/ul>\r\n","subtask2":"<ul>\r\n\t<li>$1 &le; T &le; 10$<\/li>\r\n\t<li>$1 &le; n &le; 100\\,000$<\/li>\r\n\t<li>$1 &le; v_1, v_2, \\dots, v_n &le; 1\\,000\\,000$<\/li>\r\n<\/ul>\r\n","sample_explain_1":"<ul>\r\n\t<li>Case 1: Bob can discard $25$ to minimize $E(k)$ to be $5$.<\/li>\r\n\t<li>Case 2: Discarding $36$ is optimal.<\/li>\r\n\t<li>Case 3: Discarding one of the two $30$s is optimal.<\/li>\r\n\t<li>Case 4: Discarding $24$ or $36$ is optimal.<\/li>\r\n\t<li>Case 6: Discarding $2$ is optimal.<\/li>\r\n<\/ul>\r\n"}]

시간 제한

  • Java 8: 2 초
  • Python 3: 5 초
  • PyPy3: 5 초
  • Java 8 (OpenJDK): 2 초
  • Java 11: 2 초
  • Kotlin (JVM): 2 초
  • Java 15: 2 초

채점 및 기타 정보

  • 예제는 채점하지 않는다.