시간 제한메모리 제한제출정답맞힌 사람정답 비율
1 초 128 MB111100.000%

## 문제

A bitstring, whose length is one less than a prime, might be magic. 1001 is one such string. In order to see the magic in the string let us append a non-bit x to it, regard the new thingy as a cyclic string, and make this square matrix of bits

each bit 1001 0110 0110 1001

This matrix has the same number of rows as the length of the original bitstring. The m-th row of the matrix has every m-th bit of the original string starting with the m-th bit. Because the enlarged thingy has prime length, the appended x never gets used.

If each row of the matrix is either the original bitstring or its complement, the original bitstring is magic.

## 입력

Each line of input (except last) contains a prime number p ≤ 100000. The last line contains 0 and this line should not be processed.

## 출력

For each prime number from the input produce one line of output containing the lexicographically smallest, non-constant magic bitstring of length p-1, if such a string exists, otherwise output Impossible.

## 예제 입력 1

5
3
17
47
2
79
0


## 예제 출력 1

0110
01
0010111001110100
0000100001101010001101100100111010100111101111
Impossible
001001100001011010000001001111001110101010100011000011011111101001011110011011