시간 제한 | 메모리 제한 | 제출 | 정답 | 맞힌 사람 | 정답 비율 |
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1 초 | 128 MB | 12 | 7 | 7 | 58.333% |
Given the vertices of a non-degenerate polygon (no 180-degree angles, zero-length sides, or self-intersection - but not necessarily convex), you must determine how many distinct lines of symmetry exist for that polygon. A line of symmetry is one on which the polygon, when reflected on that line, maps to itself.
Input consists of a description of several polygons.
Each polygon description consists of two lines. The first contains the integer "n" (3<=n<=1000), which gives the number of vertices on the polygon. The second contains "n" pairs of numbers (an x- and a y-value), describing the vertices of the polygon in order. All coordinates are integers from -1000 to 1000.
Input terminates on a polygon with 0 vertices.
For every polygon described, print out a line saying "Polygon #x has y symmetry line(s).", where x is the number of the polygon (starting from 1), and y is the number of distinct symmetry lines on that polygon.
4 -1 0 0 2 1 0 0 -1 3 -666 -42 57 -84 19 282 3 -241 -50 307 43 -334 498 0
Polygon #1 has 1 symmetry line(s). Polygon #2 has 0 symmetry line(s). Polygon #3 has 1 symmetry line(s).