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## 문제

Little P has just learned the shell-sort sorting algorithm. He was given some code that sorts an array of N integers in ascending order. Let A be the array to be sorted.

gap = X;
do
{  ok = 1;
for (i = 1; i<= N - gap; i++)
if (A[i] > A[i+gap])
{  temp = A[i];
A[i] = A[i+gap];
A[i+gap] = temp;
ok = 0;
}
if (gap/2 > 1) gap=gap/2; else gap=1;
}  while (ok == 0);


where i, N, X, gap, temp, ok are integers (int for C/C++).

While typing this code, little P forgot to copy line 11.

You are given the array to be sorted, A. A has N distinct elements, all between 1 and N.

You are asked to find all the values X for which the algorithm (without line 11) sorts A. We call these X values to be valid.

## 입력

The input has 2 lines. The first line has one integer, N. The next line describes A: N integers separated by one space.

## 출력

The output should have the number of valid values X on the first line. The second line should have all the valid values X, separated by one space. They should be sorted in ascending order.

## 제한

• 1 < N < 500000
• 1 ≤ X ≤ N-1

## 예제 입력 1

6
4 2 6 1 5 3


## 예제 출력 1

2
1 3


## 힌트

N is 6 and A is: 4, 2, 6, 1, 5, 3.

Valid values for X are:

• X = 1, we swap the numbers on the following positions (1,2), (3,4), (4,5), (5,6), (2,3), (4,5), (1,2), (3,4);
• X = 3, we swap the numbers on the following positions (1,4), (3,6).