|시간 제한||메모리 제한||제출||정답||맞은 사람||정답 비율|
|2 초||128 MB||58||19||14||31.818%|
Farmer John is planning his morning walk on the farm. The farm is structured like a tree: it has N barns (1 <= N <= 100,000) which are connected by N-1 edges such that he can reach any barn from any other. Farmer John wants to choose a path which starts and ends at two different barns, such that he does not traverse any edge twice. He worries that his path might be a little long, so he also wants to choose another "rest stop" barn located on this path (which is distinct from the start or the end).
Along each edge is a herd of cows, either of the Charcolais (white hair) or the Angus (black hair) variety. Being the wise man that he is, Farmer John wants to balance the forces of yin and yang that weigh upon his walk. To do so, he wishes to choose a path such that he will pass by an equal number of Charcolais herds and Angus herds-- both on the way from the start to his rest stop, and on the way from the rest stop to the end.
Farmer John is curious how many different paths he can choose that are "balanced" as described above. Two paths are different only if they consist of different sets of edges; a path should be counted only once even if there are multiple valid "rest stop" locations along the path that make it balanced.
Please help determine the number of paths Farmer John can choose!
7 1 2 0 3 1 1 2 4 0 5 2 0 6 3 1 5 7 1
There are 7 barns and 6 edges. The edges from 1 to 2, 2 to 4 and 2 to 5 have Charcolais herds along them.
No path of length 2 can have a suitable rest stop on it, so we can only consider paths of length 4. The only path that has a suitable rest stop is 3-1-2-5-7, with a rest stop at 2.