시간 제한 | 메모리 제한 | 제출 | 정답 | 맞힌 사람 | 정답 비율 |
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6 초 | 128 MB | 56 | 26 | 26 | 46.429% |
“It’s you, Captain Obvious!” – cried the evil Rabbit-Man – “you came here to foil my evil plans!”
“Yes, it’s me.” – said Captain Obvious.
“But... how did you know that I would be here, on 625 Sunflower Street?! Did you crack my evil code?”
“I did. Three days ago, you robbed a bank on 5 Sunflower Street, the next day you blew up 25 Sunflower Street, and yesterday you left quite a mess under number 125. These are all powers of 5. And last year you pulled a similar stunt with powers of 13. You seem to have a knack for Fibonacci numbers, Rabbit-Man.”
“That’s not over! I will learn... arithmetics!” – Rabbit-Man screamed as he was dragged into custody – “You will never know what to expect... Owww! Not my ears, you morons!”
“Maybe, but right now you are being arrested.” – Captain added proudly.
Unfortunately, Rabbit-Man has now indeed learned some more advanced arithmetics. To understand it, let us define the sequence Fn (being not completely unlike the Fibonacci sequence):
F1 = 1,
F2 = 2,
Fn = Fn-1 + Fn-2 for n ≥ 3.
Rabbit-Man has combined all his previous evil ideas into one master plan. On the i-th day, he does a malicious act on the spot number p(i), defined as follows:
p(i) = a1·F1i + a2·F2i + ... + ak·Fki.
The number k and the integer coefficients a1, ... , ak are fixed. Captain Obvious learned k, but does not know the coefficients. Given p(1), p(2), ... , p(k), help him to determine p(k + 1). To avoid overwhelmingly large numbers, do all the calculations modulo a fixed prime number M. You may assume that F1, F2, ... , Fn are pairwise distinct modulo M. You may also assume that there always exists a unique solution for the given input.
The first line of input contains the number of test cases T. The descriptions of the test cases follow:
The first line of each test case contains two integers k and M, 1 ≤ k ≤ 4000, 3 ≤ M ≤ 109. The second line contains k space-separated integers – the values of p(1), p(2), ... , p(k) modulo M.
Print the answers to the test cases in the order in which they appear in the input. For each test case print a single line containing one integer: the value of p(k + 1) modulo M.
2 4 619 5 25 125 6 3 101 5 11 29
30 83
The first sequence is simply 5i mod 619, therefore the next element is 55 mod 619 = 30. The second sequence is 2·1i + 3i mod 101.
ICPC > Regionals > Europe > Central European Regional Contest > CERC 2013 J번