|시간 제한||메모리 제한||제출||정답||맞은 사람||정답 비율|
|3 초||128 MB||0||0||0||0.000%|
An integer N > 1 is given. We say that an integer d > 1 is a divisor of N with multiplicity k > 0 (k is integer) if d^k | N and d^(k+1) does not divide N. For example, the number N=48=16x3 has the following divisors: 2 with multiplicity 4, 3 with multiplicity 1, 4 with multiplicity 2, 6 with multiplicity 1, and so on.
We say that a number is a divine divisor of the number N if d is a divisor of N with multiplicity k and N has no divisors with multiplicities greater than k. For example, the sole divine divisor of 48 is 2 (with multiplicity 4), and the divine divisors of 6 are: 2, 3 and 6 (each with multiplicity 1).
Your task is to determine the multiplicity of divine divisors of N and the number of its divine divisors.
The number N is given on the standard input, though in a somewhat unusual way. The first line holds a single integer n (1 ≤ n ≤ 600). The second line holds n integers ai (2 ≤ ai ≤ 10^18) separated by single spaces. These denote that N=a1⋅a2⋅…⋅an.
The first line of the standard output should hold the maximum integer k such that there exists a divisor d of N such that d^k|N. The second line should hold a single integer D that is the number of (divine) divisors of N with multiplicity k.
3 4 3 4